The order of basicity of the following compou | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The correct order of basicity is $IV < I < III < II$.$1$. Compound $IV$ (pyrrole) is the least basic because the lone pair on the nitrogen atom is

Vedclass · Accepted Answer

$IV < I < III < II$

Vedclass · Answer

(A) The correct order of basicity is $IV $1$. Compound $IV$ (pyrrole) is the least basic because the lone pair on the nitrogen atom is involved in the aromatic sextet,making it unavailable for protonation.$2$. Compound $I$ ($p$-nitroaniline) is less basic than $III$ (pyridine) because the strong electron-withdrawing $-NO_2$ group decreases the electron density on the nitrogen atom through both $-I$ and $-M$ effects.$3$. Compound $III$ (pyridine) has the nitrogen atom $sp^2$ hybridized,which is more electronegative than the $sp^3$ hybridized nitrogen in aliphatic amines,making it less basic than $II$.$4$. Compound $II$ (cyclohexylamine) is the most basic as it is a primary aliphatic amine with no electron-withdrawing groups attached,and the nitrogen is $sp^3$ hybridized.

The order of basicity of the following compounds in water is:

Similar Questions

What will be the structure of product $T$ in the following reaction?

At $NTP$,the reaction of $1 \ mol$ of methylamine with nitrous acid will yield ......... liters of nitrogen.

When chloroform reacts with ethyl amine in the presence of alcoholic $KOH$,the compound formed is

Which of the following will not give the Hoffmann bromamide reaction?

In the given carbylamine reaction,the value of $x$ (moles of $KOH$ consumed) is:
$C_6H_5NH_2 + CHCl_3 + xKOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module