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Question

(B) The standard equation for a plane electromagnetic wave is given by $E_y = E_0 \sin(\omega t + kx)$.Comparing this with the given equation $E_y = 3

Vedclass · Accepted Answer

$6.67 	imes 10^{-3} \ m$

Vedclass · Answer

(B) The standard equation for a plane electromagnetic wave is given by $E_y = E_0 \sin(\omega t + kx)$.Comparing this with the given equation $E_y = 30 \sin(2 	imes 10^{11} t + 300 \pi x)$,we identify the wave number $k$ as $300 \pi \ rad/m$.The relationship between the wave number $k$ and the wavelength $\lambda$ is given by $k = \frac{2 \pi}{\lambda}$.Rearranging for $\lambda$,we get $\lambda = \frac{2 \pi}{k}$.Substituting the value of $k$,we have $\lambda = \frac{2 \pi}{300 \pi} = \frac{1}{150} \ m$.Calculating the value,$\lambda = 0.00666... \ m = 6.67 	imes 10^{-3} \ m$.

The oscillating electric field of an electromagnetic wave is given by $E_y = 30 \sin(2 \times 10^{11} t + 300 \pi x) \ Vm^{-1}$. Then,the value of the wavelength of the electromagnetic wave is

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