The oscillator frequency of a cyclotron is $10 \,MHz$. What should be the operating magnetic field for accelerating protons (in $,T$)? (Given: mass of proton $m = 1.67 \times 10^{-27} \,kg$,charge of proton $q = 1.6 \times 10^{-19} \,C$)

$A$ cyclotron's oscillator frequency is $10 \; MHz$. What should be the operating magnetic field for accelerating protons? If the radius of its 'dees' is $60 \; cm$,what is the kinetic energy (in $MeV$) of the proton beam produced by the accelerator? $(e = 1.60 \times 10^{-19} \; C, m_p = 1.67 \times 10^{-27} \; kg, 1 \; MeV = 1.6 \times 10^{-13} \; J)$

In a cyclotron,a charged particle:

In the cyclotron, as the radius of the circular path of the charged particle increases, ($\omega$ = angular velocity, $V$ = linear velocity)

An alternating electric field,of frequency $f$,is applied across the dees (radius $\approx R$) of a cyclotron that is being used to accelerate protons (mass $\approx m$). The operating magnetic field $(B)$ used in the cyclotron and the kinetic energy $(K)$ of the proton beam,produced by it,are given by:

What do you mean by 'dees' which is used in cyclotron?