The output (X) of the logic circuit shown in | vedclass

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(C) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A.B}$.This output is fed into a $NOT$ gate (a $NAND$ gate with b

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$X = A.B$

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(C) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A.B}$.This output is fed into a $NOT$ gate (a $NAND$ gate with both inputs connected together acts as a $NOT$ gate). If the input to a $NOT$ gate is $Y$,the output is $\overline{Y}$.Here,$Y = \overline{A.B}$,so the final output $X = \overline{\overline{A.B}}$.Using the Boolean algebra property $\overline{\overline{Z}} = Z$,we get $X = A.B$.

The output $(X)$ of the logic circuit shown in the figure will be:

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