The output of a NAND gate is shown in the tru | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $NAND$ gate is a combination of an $AND$ gate followed by a $NOT$ gate.The Boolean expression for a $NAND$ gate is $Y = \overline{A \cdot B}$.Let

Vedclass · Accepted Answer

$S$

Vedclass · Answer

(C) $NAND$ gate is a combination of an $AND$ gate followed by a $NOT$ gate.The Boolean expression for a $NAND$ gate is $Y = \overline{A \cdot B}$.Let us evaluate the output $Y$ for all possible input combinations of $A$ and $B$:$1$. If $A = 0, B = 0$, then $A \cdot B = 0$, so $Y = \overline{0} = 1$.$2$. If $A = 0, B = 1$, then $A \cdot B = 0$, so $Y = \overline{0} = 1$.$3$. If $A = 1, B = 0$, then $A \cdot B = 0$, so $Y = \overline{0} = 1$.$4$. If $A = 1, B = 1$, then $A \cdot B = 1$, so $Y = \overline{1} = 0$.Comparing this with the given tables:- Table $(P)$ represents an $OR$ gate.- Table $(Q)$ represents an $XOR$ gate.- Table $(R)$ represents an $AND$ gate.- Table $(S)$ represents a $NAND$ gate.Thus, the correct truth-table is $(S)$.

The output of a $NAND$ gate is shown in the truth-table ($A$ and $B$ are inputs, $Y$ is output). Identify the correct truth-table.

Similar Questions

Converting the binary number $1011.01$ into decimal gives ....

In the given logic circuit,$A=1$ and $B=0$. The values of $Y_1$ and $Y_2$ are respectively:

Explain the types of logic systems used in digital electronics.

The output of a logic gate is low when any one of the inputs is high. Which gate does this statement describe?

Which of the following Boolean expressions is not correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module