(A) Let the oxidation number of $Cr$ be $x$. In $K_2Cr_2O_7$,the oxidation number of $K$ is $+1$ and $O$ is $-2$. The sum of oxidation numbers of all

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(A) Let the oxidation number of $Cr$ be $x$. In $K_2Cr_2O_7$,the oxidation number of $K$ is $+1$ and $O$ is $-2$. The sum of oxidation numbers of all atoms in a neutral molecule is $0$. $2(+1) + 2(x) + 7(-2) = 0$ $2 + 2x - 14 = 0$ $2x - 12 = 0$ $2x = 12$ $x = +6$ Therefore,the oxidation number of $Cr$ is $+6$.