(D) Let the oxidation number of iron $(Fe)$ be $x$.In the complex $K_4[Fe(CN)_6]$,the oxidation number of potassium $(K)$ is $+1$ and the cyanide liga

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Let the oxidation number of iron $(Fe)$ be $x$.In the complex $K_4[Fe(CN)_6]$,the oxidation number of potassium $(K)$ is $+1$ and the cyanide ligand $(CN^-)$ is $-1$.The sum of oxidation numbers in a neutral compound is $0$.$4(+1) + x + 6(-1) = 0$$4 + x - 6 = 0$$x - 2 = 0$$x = +2$.Therefore,the oxidation state of iron is $+2$.