(B) The chemical formula is $Ba(H_2PO_2)_2$.Let the oxidation number of $P$ be $x$.The oxidation number of $Ba$ is $+2$,$H$ is $+1$,and $O$ is $-2$.Su

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(B) The chemical formula is $Ba(H_2PO_2)_2$.Let the oxidation number of $P$ be $x$.The oxidation number of $Ba$ is $+2$,$H$ is $+1$,and $O$ is $-2$.Sum of oxidation numbers $= 0$.$2 + 2 \times [2 \times (+1) + x + 2 \times (-2)] = 0$$2 + 2 \times [2 + x - 4] = 0$$2 + 2 \times [x - 2] = 0$$2 + 2x - 4 = 0$$2x - 2 = 0$$2x = 2$$x = +1$.

Class 11 Chemistry Redox Reactions Oxidation number and Oxidation state

Easy

The oxidation number of phosphorus in $Ba(H_2PO_2)_2$ is

A
$-1$
B
$+1$
C
$+2$
D
$+3$

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Class 11

Chemistry Questions

Chapter

Redox Reactions

Subtopic

Oxidation number and Oxidation state

What is the correct order of decreasing oxidation state of iodine in the following compounds?

Medium

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Match the items in Column-$I$ with relevant items in Column-$II$.

Column-$I$ Column-$II$

$A$. Positively charged ion $1$. $+7$

$B$. Oxidation number of all neutral atoms $2$. $-1$

$C$. Oxidation number of hydrogen $(H^+)$ $3$. $+1$

$D$. Oxidation number of fluorine in $NaF$ $4$. $0$

$E$. Negatively charged ion $5$. Cation

$6$. Anion

Column-$I$	Column-$II$
$A$. Positively charged ion	$1$. $+7$
$B$. Oxidation number of all neutral atoms	$2$. $-1$
$C$. Oxidation number of hydrogen $(H^+)$	$3$. $+1$
$D$. Oxidation number of fluorine in $NaF$	$4$. $0$
$E$. Negatively charged ion	$5$. Cation
	$6$. Anion