The paramagnetic property of the oxygen molecule is due to the presence of unpaired electrons in

  • A
    $(\sigma 2p_x)^1$ and $(\sigma^* 2p_x)^1$
  • B
    $(\sigma 2p_x)^1$ and $(\pi 2p_y)^1$
  • C
    $(\pi^* 2p_y)^1$ and $(\pi^* 2p_z)^1$
  • D
    $(\pi^* 2p_y)^1$ and $(\pi 2p_y)^1$

Explore More

Similar Questions

Explain $H_{2}$ molecule by molecular orbital theory.

Difficult
View Solution

Which of the following pairs of species are paramagnetic?

Which one of the following sketches is not correctly matched?

Which of the following molecules is not paramagnetic in nature?

What is the total number of electrons present in bonding orbitals of $O_2$ molecule according to molecular orbital theory?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo