The percentage of nitrogen in urea is about

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(A) The chemical formula of urea is $NH_2CONH_2$.The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ g/mol$.There are $2$ nitroge

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$47$

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(A) The chemical formula of urea is $NH_2CONH_2$.The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ g/mol$.There are $2$ nitrogen atoms in one molecule of urea,so the mass of nitrogen is $2 	imes 14 = 28 \ g$.The percentage of nitrogen is calculated as $\frac{	ext{mass of nitrogen}}{	ext{molar mass of urea}} 	imes 100 = \frac{28}{60} 	imes 100 = 46.66\%$.Rounding to the nearest whole number,we get approximately $47\%$.

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