The period of oscillation of a simple pendulum is given by $T = 2\pi\sqrt{\frac{l}{g}}$ where $l$ is about $80\text{ cm}$ and is known to have $0.1\text{ cm}$ accuracy. The period is about $1.5\text{ s}$. The time of $50$ oscillations is measured by a stop watch of least count $0.1\text{ s}$. The percentage error in $g$ is nearly

If the error in the measurement of the radius of a sphere is $2\%$,then the error in the determination of the volume of the sphere will be ........ $\%$

The error in the measurement of length and mass of a cube is $3\%$ and $4\%$ respectively. The error in the measurement of its density will be (in $\%$)

The length of a pendulum is measured as $1.01 \ m$ and the time for $30$ oscillations is measured as $1 \ minute \ 3 \ s$. The error in length is $0.01 \ m$ and the error in time is $3 \ s$. The percentage error in the measurement of acceleration due to gravity is: (in $\%$)

In an experiment to determine the acceleration due to gravity $g$,the formula used for the time period of a periodic motion is $T=2 \pi \sqrt{\frac{7(R-r)}{5 g}}$. The values of $R$ and $r$ are measured to be $(60 \pm 1) \text{ mm}$ and $(10 \pm 1) \text{ mm}$,respectively. In five successive measurements,the time period is found to be $0.52 \text{ s}, 0.56 \text{ s}, 0.57 \text{ s}, 0.54 \text{ s}$ and $0.59 \text{ s}$. The least count of the watch used for the measurement of time period is $0.01 \text{ s}$. Which of the following statement$(s)$ is(are) true?
$(A)$ The error in the measurement of $r$ is $10 \%$
$(B)$ The error in the measurement of $T$ is $3.57 \%$
$(C)$ The error in the measurement of $T$ is $2 \%$
$(D)$ The error in the determined value of $g$ is $11 \%$

The radius of a sphere is $(5.3 \pm 0.1) \, cm$. The percentage error in its volume is