The plates of a parallel plate capacitor of capacity $C_1$ are moved closer together until they are half their original separation. The new capacitance $C_2$ is

  • A
    $C_2 = \frac{C_1}{2}$
  • B
    $C_2 = C_1$
  • C
    $C_2 = 2C_1$
  • D
    $C_2 = 4C_1$

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