The point of intersection of the latus rectum and axis of the parabola $y^2+4x+2y-8=0$ is

  • A
    $\left(\frac{9}{4}, -1\right)$
  • B
    $\left(\frac{5}{4}, -1\right)$
  • C
    $\left(\frac{7}{2}, \frac{5}{2}\right)$
  • D
    $\left(\frac{-5}{4}, 1\right)$

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Let $\alpha_1$ and $\alpha_2$ be the ordinates of two points $A$ and $B$ on a parabola $y^2=4ax$ and let $\alpha_3$ be the ordinate of the point of intersection of its tangents at $A$ and $B$. Then,$\alpha_3-\alpha_2=$

The equation of the normal to the parabola $y^2 = 4ax$ at the point $\left( \frac{a}{m^2}, \frac{2a}{m} \right)$ is:

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The normal at a point on the parabola $y^2=4x$ passes through $(5,0)$. If there are two more normals to this parabola passing through $(5,0)$,then the equation of one of these normals is

The normal at a point on the parabola $y^2=4x$ passes through $(5,0)$. If there are two more normals to this parabola which pass through $(5,0)$,the centroid of the triangle formed by the feet of these three normals is

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