The points where the circle $x^2+y^2-3x-4y+2=0$ cuts the $x$-axis are
- A$(1,2) \& (2,0)$
- B$(2,0) \& (3,0)$
- C$(0,2) \& (0,1)$
- D$(1,0) \& (2,0)$
Explore More
Similar Questions
The radius of a circle which touches the $y$-axis at $(0,3)$ and cuts an intercept of $8$ units with the $x$-axis is
If the line $3x - 2y + 6 = 0$ meets the $X$-axis and $Y$-axis at points $A$ and $B$ respectively,then the equation of the circle with radius $AB$ and center at $A$ is
DifficultAP EAMCET 2004
View SolutionThe parametric equations of the circle $x^2+y^2-ax-by=0$ are
The circle touching the $y$-axis at a distance $4$ units from the origin and cutting off an intercept $6$ from the $x$-axis is
The centre and radius of the circumcircle of the triangle formed by the lines $2x+3y=10$,$y=x$ and the $X$-axis are respectively:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo