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(D) The mobility $\mu$ of an electron is defined as the ratio of drift velocity $v_d$ to the electric field $E$: $\mu = \frac{v_d}{E}$.Given:Length $l

Vedclass · Accepted Answer

$3 	imes 10^{-4} \ ms^{-1}$

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(D) The mobility $\mu$ of an electron is defined as the ratio of drift velocity $v_d$ to the electric field $E$: $\mu = \frac{v_d}{E}$.Given:Length $l = 20 \ cm = 0.2 \ m$.Potential difference $V = 30 \ V$.Mobility $\mu = 2 	imes 10^{-6} \ m^2 \ V^{-1} \ s^{-1}$.The electric field $E$ is given by $E = \frac{V}{l} = \frac{30}{0.2} = 150 \ V/m$.Now,the drift velocity $v_d = \mu E$.$v_d = (2 	imes 10^{-6} \ m^2 \ V^{-1} \ s^{-1}) 	imes (150 \ V/m) = 300 	imes 10^{-6} \ ms^{-1} = 3 	imes 10^{-4} \ ms^{-1}$.Thus,the correct option is $D$.

The potential difference across a conducting wire of length $20 \ cm$ is $30 \ V$. If the electron mobility is $2 \times 10^{-6} \ m^2 \ V^{-1} \ s^{-1}$,then the drift velocity of the electrons is

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