The pressure of a medium is changed from 1.01 | vedclass

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(D) The Bulk modulus $(K)$ is defined as the ratio of the change in pressure to the fractional change in volume: $K = -\frac{\Delta p}{\Delta V/V}$.Gi

Vedclass · Accepted Answer

$1.55 	imes 10^5 \ Pa$

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(D) The Bulk modulus $(K)$ is defined as the ratio of the change in pressure to the fractional change in volume: $K = -\frac{\Delta p}{\Delta V/V}$.Given,initial pressure $P_1 = 1.01 	imes 10^5 \ Pa$ and final pressure $P_2 = 1.165 	imes 10^5 \ Pa$.The change in pressure is $\Delta p = P_2 - P_1 = (1.165 - 1.01) 	imes 10^5 \ Pa = 0.155 	imes 10^5 \ Pa$.The fractional change in volume is $\frac{\Delta V}{V} = 10\% = 0.1$.Substituting these values into the formula:$K = \frac{0.155 	imes 10^5}{0.1} = 1.55 	imes 10^5 \ Pa$.

The pressure of a medium is changed from $1.01 \times 10^5 \ Pa$ to $1.165 \times 10^5 \ Pa$ and the change in volume is $10\%$ keeping the temperature constant. The Bulk modulus of the medium is:

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