The probability that a student is not a swimm | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The selection of students who are swimmers follows a binomial distribution. Let $X$ be the number of students who are swimmers out of $n=5$ studen

Vedclass · Accepted Answer

$^{5}C_{4} \left(\frac{4}{5}\right)^{4} \left(\frac{1}{5}\right)$

Vedclass · Answer

(A) The selection of students who are swimmers follows a binomial distribution. Let $X$ be the number of students who are swimmers out of $n=5$ students.The probability that a student is not a swimmer is $q = \frac{1}{5}$.The probability that a student is a swimmer is $p = 1 - q = 1 - \frac{1}{5} = \frac{4}{5}$.The probability distribution is given by $P(X=x) = ^{n}C_{x} p^{x} q^{n-x}$.For $n=5$ and $x=4$,we have:$P(X=4) = ^{5}C_{4} \left(\frac{4}{5}\right)^{4} \left(\frac{1}{5}\right)^{5-4} = ^{5}C_{4} \left(\frac{4}{5}\right)^{4} \left(\frac{1}{5}\right)$.Thus,the correct option is $A$.

The probability that a student is not a swimmer is $\frac{1}{5}$. Then the probability that out of five students,four are swimmers is

Similar Questions

The minimum number of times a fair coin needs to be tossed so that the probability of getting at least two heads is at least $0.96$ is:

$A$ box contains $15$ green and $10$ yellow balls. If $10$ balls are randomly drawn,one by one,with replacement,then the variance of the number of green balls drawn is

For a Binomial variate $X$,the mean is $2$ and the variance is $1$. Then,the odds in favor of $X=0$ are:

$A$ fair die is thrown up to $20$ times. The probability that on the $10^{th}$ throw,the fourth six appears is:

In $3$ trials of a binomial distribution,the probability of $2$ successes is $9$ times the probability of $3$ successes. Then the probability of success in each trial is

Vedclass Test Series

Exam Paper Generator

Online Exam Module