The product (C) in the following sequence of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The starting material is propylbenzene. Oxidation with $KMnO_4-KOH$ followed by acidification $(H_3O^+)$ converts the alkyl side chain into a

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) $1$. The starting material is propylbenzene. Oxidation with $KMnO_4-KOH$ followed by acidification $(H_3O^+)$ converts the alkyl side chain into a carboxylic acid group,yielding benzoic acid $(B)$.$2$. Benzoic acid is then subjected to electrophilic aromatic substitution with $Br_2$ in the presence of $FeBr_3$. Since the $-COOH$ group is meta-directing,the product $(C)$ is $m$-bromobenzoic acid.$3$. The structure of $m$-bromobenzoic acid contains a benzene ring (which has $3$ $\pi$ bonds) and a carbonyl group ($C=O$,which has $1$ $\pi$ bond).$4$. Total $\pi$ bonds $= 3 + 1 = 4$.

The product $(C)$ in the following sequence of reactions has . . . . . . . . $\pi$ bonds.

Similar Questions

Identify the reaction which will $NOT$ produce an alcohol as a major product.

The strongest acid among the following is

The most acidic of the following is

Which of the following compounds is obtained when benzoic acid is treated with conc. $H_{2}SO_{4}$ and conc. $HNO_{3}$?

Identify the reagent used in the following reaction.
Benzoic acid $\xrightarrow{\text{Reagent}}$ Benzoyl chloride $+$ Phosphorus oxychloride $+$ Hydrogen chloride

Vedclass Test Series

Exam Paper Generator

Online Exam Module