The product of the above reaction is:

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Question

(B) The given reaction is the Balz-Schiemann reaction,where benzenediazonium tetrafluoroborate $(C_6H_5N_2^+BF_4^-)$ is heated to produce fluorobenzen

Vedclass · Accepted Answer

Nitrobenzene

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(B) The given reaction is the Balz-Schiemann reaction,where benzenediazonium tetrafluoroborate $(C_6H_5N_2^+BF_4^-)$ is heated to produce fluorobenzene $(C_6H_5F)$.However,the reaction conditions provided in the question $(NaNO_2, Cu, \Delta)$ are characteristic of the Gattermann reaction or Sandmeyer-type reactions,which typically replace the diazonium group with other substituents like $-NO_2$ or $-Cl$ depending on the reagents.Specifically,the reaction of benzenediazonium salts with $NaNO_2$ in the presence of copper powder is a method to introduce a nitro group,forming nitrobenzene $(C_6H_5NO_2)$.Therefore,the product is nitrobenzene.

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