The proposition $(\sim p) \vee (p \wedge \sim q)$ is equivalent to

  • A
    $p \wedge (\sim q)$
  • B
    $p \rightarrow (\sim q)$
  • C
    $p \vee q$
  • D
    $q \rightarrow p$

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Similar Questions

Given below are two pairs of statements. Combine these two statements using "if and only if".
$p:$ If the sum of digits of a number is divisible by $3,$ then the number is divisible by $3.$
$q:$ If a number is divisible by $3,$ then the sum of its digits is divisible by $3.$

Which of the following statements is $NOT$ logically equivalent to $(p \to \sim p) \to (p \to q)$?

$p$ and $q$ are two logical statements. If $r: p \rightarrow (\sim p \vee q)$ has truth value false,then the truth values of $p$ and $q$ are respectively:

The negation of $\forall n \in N, n+7 > 6$ is ....

The logical statement $(p$ $\rightarrow q) \wedge (p$ $\rightarrow \sim p)$ is equivalent to

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