The radius of a sphere is 3.5, cm. Find the c | vedclass

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(B) Given,the radius of the sphere $(r) = 3.5\, cm = \frac{7}{2}\, cm$.The surface area of a sphere is given by the formula $A = 4\pi r^{2}$.Substitut

Vedclass · Accepted Answer

$23100$

Vedclass · Answer

(B) Given,the radius of the sphere $(r) = 3.5\, cm = \frac{7}{2}\, cm$.The surface area of a sphere is given by the formula $A = 4\pi r^{2}$.Substituting the values:$A = 4 	imes \frac{22}{7} 	imes \left(\frac{7}{2}ight)^{2}$$A = 4 	imes \frac{22}{7} 	imes \frac{49}{4} = 22 	imes 7 = 154\, cm^{2}$.The cost of plating gold is ₹ $150$ per $cm^{2}$.Total cost = $	ext{Surface area} 	imes 	ext{Rate}$Total cost = $154 	imes 150 = 23,100$.Therefore,the cost of plating gold on its surface is ₹ $23,100$.

The radius of a sphere is $3.5\, cm$. Find the cost of plating gold on its surface at the rate of ₹ $150$ per $cm^{2}$. (in ₹)

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