The radius of the orbit of an electron in a h | vedclass

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(A) The time period of revolution of the electron is given by $T = \frac{2\pi r}{v}$.Since current $i$ is defined as the rate of flow of charge,$i = \

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(A) The time period of revolution of the electron is given by $T = \frac{2\pi r}{v}$.Since current $i$ is defined as the rate of flow of charge,$i = \frac{e}{T}$.Substituting $T$,we get $i = \frac{ev}{2\pi r}$.Given: $e = 1.6 	imes 10^{-19} \ C$,$v = 2 	imes 10^6 \ m/s$,and $r = 0.5 \ \mathring{A} = 0.5 	imes 10^{-10} \ m$.$i = \frac{1.6 	imes 10^{-19} 	imes 2 	imes 10^6}{2 	imes 3.14 	imes 0.5 	imes 10^{-10}}$.$i = \frac{3.2 	imes 10^{-13}}{3.14 	imes 10^{-10}} \approx 1.019 	imes 10^{-3} \ A$.Converting to $mA$,$i \approx 1 \ mA$.

The radius of the orbit of an electron in a hydrogen atom is $0.5 \ \mathring{A}$. The speed of the electron is $2 \times 10^6 \ m/s$. The current in the loop due to the motion of the electron is ............. $mA$.

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