The rate of reaction between $A$ and $B$ increases by a factor of $100$ when the concentration of $A$ is increased $10$ folds. The order of reaction with respect to $A$ is

  • A
    $10$
  • B
    $1$
  • C
    $4$
  • D
    $2$

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Exp. $[A] \ (mol \ L^{-1})$ $[B_2] \ (mol \ L^{-1})$ Rate $(mol \ L^{-1} \ S^{-1})$
$1$ $0.50$ $0.50$ $1.6 \times 10^{-4}$
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$3$ $1.00$ $1.00$ $3.2 \times 10^{-4}$

Determine the rate law for the reaction.

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