(B) The rate law for the reaction is $r = k [NO]^2 [O_2]^1$. When the volume of the vessel is doubled,the concentration of each reactant is halved bec

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reduce to one-eighth of its initial rate

(B) The rate law for the reaction is $r = k [NO]^2 [O_2]^1$. When the volume of the vessel is doubled,the concentration of each reactant is halved because $[C] = n/V$. New concentration $[NO]' = [NO]/2$ and $[O_2]' = [O_2]/2$. New rate $r' = k ([NO]/2)^2 ([O_2]/2)^1$. $r' = k ([NO]^2 / 4) ([O_2] / 2) = (1/8) k [NO]^2 [O_2] = (1/8) r$. Thus,the rate reduces to one-eighth of its initial rate.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

The rate of the simple reaction,$2NO + O_2 \to 2NO_2$,when the volume of the reaction vessel is doubled:

A
will grow eight times of its initial rate
B
reduce to one-eighth of its initial rate
C
will grow four times of its initial rate
D
reduce to one-fourth of its initial rate

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The rate of the simple reaction,$2NO + O_2 \to 2NO_2$,when the volume of the reaction vessel is doubled:

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