The ratio of milk and water in $66$ $litres$ of adulterated milk is $5:1$. Water is added to it to make the ratio $5:3$. The quantity of water added is (in $litres$):

  • A
    $20$
  • B
    $22$
  • C
    $24$
  • D
    $28$

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Milk and water are mixed in vessel $A$ in the ratio of $5:2$ and in vessel $B$ in the ratio of $8:5$. In what ratio should quantities be taken from the two vessels so as to form a mixture in which milk and water will be in the ratio of $9:4$?

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