(C) To find the container with the minimum quantity of milk relative to water,we calculate the fraction of milk in each mixture:$1$. First container:

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(C) To find the container with the minimum quantity of milk relative to water,we calculate the fraction of milk in each mixture:$1$. First container: $\frac{5}{5+3} = \frac{5}{8} = 0.625$$2$. Second container: $\frac{2}{2+1} = \frac{2}{3} \approx 0.666$$3$. Third container: $\frac{3}{3+2} = \frac{3}{5} = 0.600$$4$. Fourth container: $\frac{7}{7+4} = \frac{7}{11} \approx 0.636$Comparing the values: $0.600 The minimum value is $0.6$,which corresponds to the third container.

Competitive Quantitative Aptitude Mixture and Alligation Mixture and Alligation

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The ratio of milk and water in mixtures of four containers are $5:3$,$2:1$,$3:2$,and $7:4$,respectively. In which container is the quantity of milk,relative to water,the minimum?

A
$First$
B
$Second$
C
$Third$
D
$Fourth$

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The ratio of milk and water in mixtures of four containers are $5:3$,$2:1$,$3:2$,and $7:4$,respectively. In which container is the quantity of milk,relative to water,the minimum?

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$729 \ ml$ of a mixture contains milk and water in the ratio $7:2$. How much more water is to be added to get a new mixture containing milk and water in the ratio $7:3$? (in $ml$)

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