The ratio of radii of the second orbit of a h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For hydrogen and hydrogen-like atoms,the radius of the $n^{th}$ orbit is given by the formula: $r_n \propto \frac{n^2}{Z}$,where $n$ is the orbit

Vedclass · Accepted Answer

$1: 2$

Vedclass · Answer

(C) For hydrogen and hydrogen-like atoms,the radius of the $n^{th}$ orbit is given by the formula: $r_n \propto \frac{n^2}{Z}$,where $n$ is the orbit number and $Z$ is the atomic number.For a hydrogen atom $(H)$,$Z = 1$. The radius of the second orbit $(n = 2)$ is $r_2 = \frac{2^2}{1} = 4$.For a helium ion $(He^{+})$,$Z = 2$. The radius of the fourth orbit $(n = 4)$ is $r_4 = \frac{4^2}{2} = \frac{16}{2} = 8$.The ratio of the radii is $\frac{r_2}{r_4} = \frac{4}{8} = \frac{1}{2}$,which is $1: 2$.

The ratio of radii of the second orbit of a hydrogen atom to the fourth orbit of a $He^{+}$ ion is:

Similar Questions

For a lithium atom,what can be said about the angular momentum and energy values for the permitted orbit of its third electron?

In the case of a hydrogen atom,when an electron falls from a higher energy level to the $M$ shell,the corresponding spectral line will form a part of:

The ionization enthalpy of a hydrogen atom is $1.312 \times 10^6 \ J \ mol^{-1}$. The energy required to excite the electron in the atom from $n= 1$ to $n= 2$ is

The ground state energy of a $H$ atom is given as $-13.6 \, eV$. The energy of the second excited state will be .......... $eV$.

Which one of the following statements is not correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module