The rationalizing factor of 2sqrt{3} - sqrt{7 | vedclass

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(B) To find the rationalizing factor of an expression of the form $a - b$,we multiply it by its conjugate $a + b$ to eliminate the square roots.Given

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$2\sqrt{3} + \sqrt{7}$

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(B) To find the rationalizing factor of an expression of the form $a - b$,we multiply it by its conjugate $a + b$ to eliminate the square roots.Given expression: $2\sqrt{3} - \sqrt{7}$.Its conjugate is $2\sqrt{3} + \sqrt{7}$.Multiplying these gives: $(2\sqrt{3} - \sqrt{7})(2\sqrt{3} + \sqrt{7}) = (2\sqrt{3})^2 - (\sqrt{7})^2 = (4 	imes 3) - 7 = 12 - 7 = 5$.Since $5$ is a rational number,the rationalizing factor is $2\sqrt{3} + \sqrt{7}$.

The rationalizing factor of $2\sqrt{3} - \sqrt{7}$ is:

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