The reactant which is entirely consumed in a reaction is known as the limiting reagent. In the reaction $2A + 4B \to 3C + 4D$,when $5 \ mol$ of $A$ react with $6 \ mol$ of $B$,then:
$(i)$ Which is the limiting reagent?
$(ii)$ Calculate the amount of $C$ formed.
$(i)$ Which is the limiting reagent?
$(ii)$ Calculate the amount of $C$ formed.
(B) The given reaction is: $2A + 4B \to 3C + 4D$.
Given moles of $A = 5 \ mol$ and $B = 6 \ mol$.
To find the limiting reagent,we calculate the moles of product $C$ formed by each reactant:
For $A$: $2 \ mol$ of $A$ produces $3 \ mol$ of $C$. Therefore,$5 \ mol$ of $A$ produces $\frac{3}{2} \times 5 = 7.5 \ mol$ of $C$.
For $B$: $4 \ mol$ of $B$ produces $3 \ mol$ of $C$. Therefore,$6 \ mol$ of $B$ produces $\frac{3}{4} \times 6 = 4.5 \ mol$ of $C$.
Since reactant $B$ produces a smaller amount of product $C$,$B$ is the limiting reagent.
The amount of $C$ formed is $4.5 \ mol$.
Given moles of $A = 5 \ mol$ and $B = 6 \ mol$.
To find the limiting reagent,we calculate the moles of product $C$ formed by each reactant:
For $A$: $2 \ mol$ of $A$ produces $3 \ mol$ of $C$. Therefore,$5 \ mol$ of $A$ produces $\frac{3}{2} \times 5 = 7.5 \ mol$ of $C$.
For $B$: $4 \ mol$ of $B$ produces $3 \ mol$ of $C$. Therefore,$6 \ mol$ of $B$ produces $\frac{3}{4} \times 6 = 4.5 \ mol$ of $C$.
Since reactant $B$ produces a smaller amount of product $C$,$B$ is the limiting reagent.
The amount of $C$ formed is $4.5 \ mol$.
Explore More
Similar Questions
What will be the volume of the mixture after the reaction? $litre$
$NH_3(4 \ litre) + HCl(1.5 \ litre) \to NH_4Cl(s)$
$NH_3(4 \ litre) + HCl(1.5 \ litre) \to NH_4Cl(s)$
Difficult
View SolutionHow much amount of $Al_2O_3$ will be formed when $5.4 \ g$ of $Al$ reacts with $10 \ g$ of $O_2$? .......... $g$
Easy
View SolutionIn the reaction: $4A + 2B + 3C \to A_4B_2C_3,$ what will be the number of moles of product formed,starting from $1 \, mole$ of $A, 0.6 \, mole$ of $B$ and $0.72 \, mole$ of $C$?
Medium
View Solution$20$ moles of $A$ and $14$ moles of $B$ are mixed and allowed to react according to the equation $A + 2B \rightarrow 3C$. What is the maximum number of moles of $C$ which could be prepared?
Medium
View Solution$92 \ g$ of $NO_{2(g)}$ and $32 \ g$ of $O_{2(g)}$ are taken in a rigid container. At a constant temperature,they react to produce $N_2O_{5(g)}$. The pressure in the container after the reaction is observed to be $\frac{7}{8} P$,where $P$ is the initial pressure of the gaseous mixture. The percentage yield of the reaction is ....$\%$
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo