The reaction 2A + B_{2} rightarrow 2AB is an | vedclass

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(A) The given reaction is $2A + B_{2} \rightarrow 2AB$.Since it is an elementary reaction,the rate law is given by $r_{1} = k[A]^{2}[B_{2}]$.When the

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$27$

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(A) The given reaction is $2A + B_{2} \rightarrow 2AB$.Since it is an elementary reaction,the rate law is given by $r_{1} = k[A]^{2}[B_{2}]$.When the volume of the reaction vessel is reduced by a factor of $3$,the concentration of each reactant increases by a factor of $3$ (since $C = n/V$).Let the new concentrations be $[A]' = 3[A]$ and $[B_{2}]' = 3[B_{2}]$.The new rate $r_{2}$ is $r_{2} = k(3[A])^{2}(3[B_{2}])$.$r_{2} = k \cdot 9[A]^{2} \cdot 3[B_{2}] = 27 \cdot k[A]^{2}[B_{2}] = 27 \cdot r_{1}$.Thus,the rate of reaction increases by a factor of $27$.

$Exp. \ No.$	$[A]$	$[B]$	$Rate$
$1.$	$1.0$	$0.15$	$4.2 \times 10^{-6}$
$2.$	$2.0$	$0.15$	$8.4 \times 10^{-6}$
$3.$	$1.0$	$0.20$	$5.6 \times 10^{-6}$

The reaction $2A + B_{2} \rightarrow 2AB$ is an elementary reaction. For a certain quantity of reactants,if the volume of the reaction vessel is reduced by a factor of $3,$ the rate of the reaction increases by a factor of $.....$. (Round off to the Nearest Integer).

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$A$ study of chemical kinetics of the reaction $A + B \to$ Products,gave the following data at $25 \ ^oC$.

$Exp. \ No.$ $[A]$ $[B]$ $Rate$

$1.$ $1.0$ $0.15$ $4.2 \times 10^{-6}$

$2.$ $2.0$ $0.15$ $8.4 \times 10^{-6}$

$3.$ $1.0$ $0.20$ $5.6 \times 10^{-6}$

Find out the rate law.

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