The reaction of $Pb(NO_3)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

  • A
    $PbCl_2$
  • B
    $PbCl_4$
  • C
    $[PbCl_4]^{2-}$
  • D
    $[PbCl_6]^{2-}$

Explore More

Similar Questions

An aqueous solution of $CoCl_2$ on addition of excess of concentrated $HCl$ turns blue due to the formation of:

Assign $A, B, C, D$ from the given type of reaction: $Cd(CN)_2 \downarrow + 2KCN \longrightarrow K_2[Cd(CN)_4]$

Violet colour of $[Ti(H_2O)_6]Cl_3$ on heating changes to $........$

Which of the following coordination compounds acts as a non-electrolyte in solution?

Arrange the ligands $NH_3, en, Cl^-,$ and $CO$ in the increasing order of their field strength (spectrochemical series).

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo