The reaction of $Q$ with $PhSNa$ yields an organic compound (major product) that gives a positive Carius test on treatment with $Na_2O_2$ followed by the addition of $BaCl_2$. The correct option$(s)$ for $Q$ is (are):

In the Carius method, $0.2425 \ g$ of an organic compound gave $0.5253 \ g$ of silver chloride. The percentage of chlorine in the organic compound is: (in $\%$)

$0.1 \ g$ of an organic compound was analyzed by the Kjeldahl method. The $NH_3$ produced was absorbed in $30 \ mL$ of $N/5$ $H_2SO_4$. The remaining acid required $20 \ mL$ of $N/10$ $NaOH$ for neutralization. Calculate the percentage of nitrogen in the organic compound.

When $1 \ g$ of compound $(X)$ is subjected to Kjeldahl's method for the estimation of nitrogen, $15 \ mL$ of $1 \ M$ $H_2SO_4$ was neutralized by the ammonia evolved. The percentage of nitrogen in compound $(X)$ is:

What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

Calculate the percentage of nitrogen in $0.25 \ g$ of an organic compound if $38 \ cm^3$ of $N_2$ gas is evolved at $300 \ K$ and $96 \ kPa$ pressure. (Given: $1 \ atm = 101.3 \ kPa$)