The reaction of $C_6H_5CH=CHCH_3$ with $HBr$ produces

  • A
    $C_6H_5CH_2CH_2CH_2Br$
  • B
    Option B
  • C
    $C_6H_5CH(Br)CH_2CH_3$
  • D
    $C_6H_5CH_2CH(Br)CH_3$

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