The refractive index of a glass convex lens i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Refractive index of glass $\mu_g = 1.5$,refractive index of air $\mu_a = 1$,refractive index of liquid $\mu_l = 1.25$,and radii of curvatur

Vedclass · Accepted Answer

$2:5$

Vedclass · Answer

(B) Given: Refractive index of glass $\mu_g = 1.5$,refractive index of air $\mu_a = 1$,refractive index of liquid $\mu_l = 1.25$,and radii of curvature $R_1 = 20 ~cm, R_2 = -20 ~cm$.Using the Lens Maker's Formula: $P = \frac{1}{f} = (\frac{\mu_g}{\mu_m} - 1)(\frac{1}{R_1} - \frac{1}{R_2})$.Power in air $(P_a)$: $P_a = (\frac{1.5}{1} - 1)(\frac{1}{20} - \frac{1}{-20}) = (0.5)(\frac{2}{20}) = 0.5 	imes 0.1 = 0.05 ~cm^{-1}$.Power in liquid $(P_l)$: $P_l = (\frac{1.5}{1.25} - 1)(\frac{1}{20} - \frac{1}{-20}) = (1.2 - 1)(0.1) = 0.2 	imes 0.1 = 0.02 ~cm^{-1}$.Ratio of power in liquid to power in air: $\frac{P_l}{P_a} = \frac{0.02}{0.05} = \frac{2}{5}$.

The refractive index of a glass convex lens is $1.5$. The radius of curvature of each of the two surfaces of the lens is $20 ~cm$. The ratio of the power of the lens when immersed in a liquid of refractive index $1.25$ to that when placed in air is:

Similar Questions

The metal used for the de-bromination reaction of $1, 2-dibromoethane$ is:

$A$ $4 \mu F$ capacitor is charged by a $200 \ V$ battery. It is then disconnected from the supply and connected to another uncharged $2 \mu F$ capacitor. During the process,the loss of energy (in $J$) is:

In a $\triangle ABC$,if $\frac{\cos A}{a} = \frac{\cos B}{b} = \frac{\cos C}{c}$,then $\triangle ABC$ is

Which one of the following is not a bioindicator of water pollution?

$A$ ball is allowed to fall from a height of $10\, m$. If there is $40\%$ loss of energy due to impact,then after one impact,the ball will rise to a height of ......... $m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module