The relative basic strength of the compounds | vedclass

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Question

(C) The correct order of relative basic strength is $NH_3 > N_2H_4 > NH_2OH$. In $NH_3$,the lone pair on nitrogen is completely available for donation

Vedclass · Accepted Answer

$NH_3 > N_2H_4 > NH_2OH$

Vedclass · Answer

(C) The correct order of relative basic strength is $NH_3 > N_2H_4 > NH_2OH$. In $NH_3$,the lone pair on nitrogen is completely available for donation,making it the most basic. $N_2H_4$ and $NH_2OH$ are derivatives of $NH_3$ where one $H$ atom is replaced by $-NH_2$ and $-OH$ groups respectively. The $-OH$ group is highly electron-withdrawing due to the high electronegativity of the oxygen atom,which significantly decreases the electron density on the nitrogen atom. The $-I$ effect of the $-NH_2$ group is less than that of the $-OH$ group. Therefore,the basic strength decreases as the electron-withdrawing nature of the substituent increases,leading to the order $NH_3 > N_2H_4 > NH_2OH$.

The relative basic strength of the compounds is correctly shown in the option.

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