The resistance of $0.05\, M$ solution of oxalic acid is $200\, \Omega$ and the cell constant is $2.0\, cm^{-1}$. The equivalent conductance in $S\, cm^2\, eq^{-1}$ will be:

Molar ionic conductivities of a divalent cation and a divalent anion are $57 \ S \ cm^2 \ mol^{-1}$ and $73 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of a solution of an electrolyte containing these ions will be:

Metallic conductors and semiconductors are heated separately. What are the changes with respect to conductivity?

Calculate the molar conductivity of $0.2 \text{ M}$ $KCl$ solution at $298 \text{ K}$ if the conductivity $(k)$ is $0.0248 \text{ } \Omega^{-1} \text{cm}^{-1}$.

Molar conductivities at infinite dilution $\wedge_{m}^{\circ}$ for $Ba(OH)_2$,$BaCl_2$ and $NH_4Cl$ are $457.0$,$240.6$ and $213.0 \ S \ cm^2 \ mol^{-1}$ respectively. The $\wedge_{m}^{\circ}$ for ammonium hydroxide (in $S \ cm^2 \ mol^{-1}$) is (in $.2$)

$\Lambda_{m(HAc)}^0$ is equal to . . . . . . .