(C) The cell constant $G^*$ is given by $G^* = \frac{l}{a} = \frac{2.2 \, cm}{4.4 \, cm^2} = 0.5 \, cm^{-1} = 50 \, m^{-1}$.Conductivity $\kappa = \fr

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(C) The cell constant $G^*$ is given by $G^* = \frac{l}{a} = \frac{2.2 \, cm}{4.4 \, cm^2} = 0.5 \, cm^{-1} = 50 \, m^{-1}$.Conductivity $\kappa = \frac{1}{R} \times G^* = \frac{1}{50 \, \Omega} \times 50 \, m^{-1} = 1 \, S \, m^{-1}$.Molar conductivity $\Lambda_m = \frac{\kappa}{C}$.Given $C = 0.5 \, M = 0.5 \, mol \, L^{-1} = 0.5 \times 10^3 \, mol \, m^{-3} = 500 \, mol \, m^{-3}$.$\Lambda_m = \frac{1 \, S \, m^{-1}}{500 \, mol \, m^{-3}} = 0.002 \, S \, m^2 \, mol^{-1}$.Thus,option $C$ is correct.

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Medium

The resistance of a $0.5 \, M$ solution of an electrolyte in a cell was found to be $50 \, \Omega$. If the electrodes in the cell are $2.2 \, cm$ apart and have an area of $4.4 \, cm^2$,then the molar conductivity (in $S \, m^2 \, mol^{-1}$) of the solution is:

A
$0.2$
B
$0.02$
C
$0.002$
D
none of these

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Electrochemistry

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Conductor and Conductance and Cell constant

The ionic conductances of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. The equivalent conductance of $BaCl_2$ at infinite dilution is ..... (in $.5$)

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What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$ and conductivity $0.012 \text{ }\Omega^{-1}\text{cm}^{-1}$ at $25 \text{ }^\circ\text{C}$ (in M)?

DifficultMHT CET 2026

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The equivalent conductivities of $Ba^{2+}$ and $Cl^-$ ions at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. What is the equivalent conductivity of $BaCl_2$ at infinite dilution?

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Which among the following concentrations of $KCl$ solution is not used to determine the cell constant of a conductivity cell?

MediumMHT CET 2022

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Provide the graph of $\Lambda_{m}$ versus $c^{1/2}$ for aqueous solutions of strong and weak electrolytes,and clarify their differences and uses.

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The resistance of a $0.5 \, M$ solution of an electrolyte in a cell was found to be $50 \, \Omega$. If the electrodes in the cell are $2.2 \, cm$ apart and have an area of $4.4 \, cm^2$,then the molar conductivity (in $S \, m^2 \, mol^{-1}$) of the solution is:

Similar Questions

The ionic conductances of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. The equivalent conductance of $BaCl_2$ at infinite dilution is ..... (in $.5$)

What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$ and conductivity $0.012 \text{ }\Omega^{-1}\text{cm}^{-1}$ at $25 \text{ }^\circ\text{C}$ (in M)?

The equivalent conductivities of $Ba^{2+}$ and $Cl^-$ ions at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. What is the equivalent conductivity of $BaCl_2$ at infinite dilution?

Which among the following concentrations of $KCl$ solution is not used to determine the cell constant of a conductivity cell?

Provide the graph of $\Lambda_{m}$ versus $c^{1/2}$ for aqueous solutions of strong and weak electrolytes,and clarify their differences and uses.

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