Which among the following concentrations of $KCl$ solution is not used to determine the cell constant of a conductivity cell?

The resistance of a conductivity cell of $0.1 \ M$ $KCl$ solution is $120 \ \Omega$ and conductivity is $1.64 \times 10^{-4} \ S \ cm^{-1}$. What is the value of cell constant (in $cm^{-1}$)?

In infinite dilution,the equivalent conductances of $Ba^{2+}$ and $Cl^{-}$ are $127$ and $76 \ ohm^{-1} cm^2 eqv^{-1}$ respectively. The equivalent conductivity of $BaCl_2$ at infinite dilution is: (in $.5$)

What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$ and conductivity $0.012 \text{ }\Omega^{-1}\text{cm}^{-1}$ at $25 \text{ }^\circ\text{C}$ (in M)?

If the values of $\Lambda_{\infty}$ of $NH_4Cl$,$NaOH$ and $NaCl$ are $130$,$217$ and $109 \ ohm^{-1} \ cm^2 \ equiv^{-1}$ respectively,the $\Lambda_{\infty}$ of $NH_4OH$ in $ohm^{-1} \ cm^2 \ equiv^{-1}$ is:

The conductivity of $0.012 \ M$ $NaBr$ solution is $2.67 \times 10^{-4} \ S \ cm^{-1}$. What is its molar conductivity?