The resistance of a galvanometer is 50,Omega | vedclass

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(B) To convert a galvanometer into an ammeter,a shunt resistance $S$ must be connected in parallel with the galvanometer.Given:Galvanometer resistance

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$5 	imes 10^{-4}\,\Omega$ in parallel

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(B) To convert a galvanometer into an ammeter,a shunt resistance $S$ must be connected in parallel with the galvanometer.Given:Galvanometer resistance $G = 50\,\Omega$Full-scale deflection current $i_g = 100\,\mu A = 100 	imes 10^{-6}\,A = 10^{-4}\,A$Desired range of ammeter $i = 10\,A$The formula for shunt resistance is $S = \frac{G \cdot i_g}{i - i_g}$.Substituting the values:$S = \frac{50 	imes 10^{-4}}{10 - 10^{-4}}$Since $10^{-4}$ is very small compared to $10$,we can approximate the denominator as $10$.$S \approx \frac{50 	imes 10^{-4}}{10} = 5 	imes 10^{-4}\,\Omega$.Thus,a resistance of $5 	imes 10^{-4}\,\Omega$ must be connected in parallel.

The resistance of a galvanometer is $50\,\Omega$ and the current required to give full-scale deflection is $100\,\mu A$. In order to convert it into an ammeter reading up to $10\,A$,it is necessary to put a resistance of

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