The resistivity of a pure semiconductor is $0.5 \ \Omega m$. If the electron and hole mobility are $0.39 \ m^2 / V-s$ and $0.19 \ m^2 / V-s$ respectively,then calculate the intrinsic carrier concentration.

The addition of antimony atoms to a sample of intrinsic germanium transforms it into a material which is:

Pure $Si$ at $500\,K$ has equal number of electron $(n_e)$ and hole $(n_h)$ concentrations of $1.5 \times 10^{16}\,m^{-3}$. Doping by indium increases $n_h$ to $4.5 \times 10^{22}\,m^{-3}$. The doped semiconductor is of

For a pure $Si$ crystal at $300 \ K$,the electron $(n_e)$ and hole $(n_h)$ concentrations are equal,being $1.5 \times 10^{16} \ m^{-3}$. On doping with Indium,the hole concentration increases to $4.5 \times 10^{22} \ m^{-3}$. Calculate the new electron concentration $(n_e)$ in the doped $Si$.

The number of silicon atoms per $m^3$ is $5 \times 10^{28}$. This is doped with $4.5 \times 10^{21}$ atoms $/ m^3$ of Arsenic. The ratio of the number of electrons to the number of holes after doping is (Take $n_i = 1.5 \times 10^{16} / m^3$)

An intrinsic semiconductor is converted into $N$-type extrinsic semiconductor by doping it with