The resonance frequency of an $L-C-R$ $AC$ circuit is $\nu_{0}$. If the capacitance is made $4$ times its initial value,then the new resonance frequency will become . . . . . . .

  • A
    $\frac{\nu_{0}}{4}$
  • B
    $2 \nu_{0}$
  • C
    $\nu_{0}$
  • D
    $\frac{\nu_{0}}{2}$

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