The root mean square velocity of an ideal gas in a closed container of fixed volume is increased from $5 \times 10^4 \ cm \ s^{-1}$ to $10 \times 10^4 \ cm \ s^{-1}$. Which of the following statements correctly explains how the change is accomplished?

  • A
    By heating the gas,the temperature is doubled
  • B
    By heating the gas,the pressure is quadrupled (i.e.,made four times)
  • C
    By heating the gas,the temperature is quadrupled
  • D
    By heating the gas,the pressure is doubled

Explore More

Similar Questions

The gas equation $PV = nRT$ is obeyed by:

For $1 \ mol$ of an ideal gas at a constant temperature $T,$ the plot of $(\log \ P)$ against $(\log \ V)$ is a ($P :$ Pressure,$V:$ Volume)

$V_0$ and $V_t$ are the volumes of a fixed mass of an ideal gas at $0^\circ \text{C}$ and $t^\circ \text{C}$ respectively at constant pressure. Find the ratio $V_t / V_0$.

$A$ gas obeys Charles's law in the temperature range $0-500 \ K$ at a given pressure. Its volume changes to zero at a temperature of:

The deviation of a gas from ideal behavior can be expressed by which of the following?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo