The roots of the quadratic equation 4x^{2} + | vedclass

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(C) For a quadratic equation $ax^{2} + bx + c = 0$,the nature of the roots is determined by the discriminant $D = b^{2} - 4ac$.Here,$a = 4$,$b = 4$,an

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unequal and rational

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(C) For a quadratic equation $ax^{2} + bx + c = 0$,the nature of the roots is determined by the discriminant $D = b^{2} - 4ac$.Here,$a = 4$,$b = 4$,and $c = -3$.Calculating the discriminant: $D = (4)^{2} - 4(4)(-3) = 16 + 48 = 64$.Since $D > 0$,the roots are real and unequal.Since $D = 64$ is a perfect square,the roots are rational.Therefore,the roots are unequal and rational.

The roots of the quadratic equation $4x^{2} + 4x - 3 = 0$ are

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