(C) Given the equation $ix^2 - 4x - 4i = 0$. Dividing the entire equation by $i$ (or multiplying by $-i$): $x^2 - \frac{4}{i}x - 4 = 0$ Since $\frac{1

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(C) Given the equation $ix^2 - 4x - 4i = 0$. Dividing the entire equation by $i$ (or multiplying by $-i$): $x^2 - \frac{4}{i}x - 4 = 0$ Since $\frac{1}{i} = -i$,we get: $x^2 + 4ix - 4 = 0$ This can be written as: $x^2 + 2ix + 2ix + (2i)^2 = 0$ $(x + 2i)^2 = 0$ Therefore,the roots are $x = -2i, -2i$.