The scale of a galvanometer is divided into $160$ equal divisions. The galvanometer shows full scale deflection of $16$ mA and maximum voltage is $80$ mV. Now the range is changed so that the galvanometer reads $160$ $V$. The required resistance to be connected is

  • A
    $9995 \Omega$ in series.
  • B
    $4995 \Omega$ in series.
  • C
    $9.5 \times 10^{-3} \Omega$ in parallel.
  • D
    $4.95 \times 10^{-3} \Omega$ in parallel.

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Similar Questions

Consider two identical galvanometers and two identical resistors with resistance $R$. If the internal resistance of the galvanometers is $R_G < R/2$,which of the following configurations yield the maximum voltage range and maximum current range?

The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:

Explain the difficulties encountered when using a galvanometer directly as an ammeter.

$A$ galvanometer has resistance $G \ \Omega$ and $I_g$ is the current flowing through it which produces full-scale deflection. $S_1$ is the value of the shunt which converts it into an ammeter of range $0$ to $3I$,and $S_2$ is the shunt value which converts it into an ammeter of range $0$ to $4I$. The ratio $S_2:S_1$ is:

What is a shunt? Explain its function in a circuit,obtain the formula for the shunt,and explain its uses.

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