The sequence frac{5}{sqrt{7}}, frac{6}{sqrt{7 | vedclass

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(C) To determine the type of sequence,we check the difference between consecutive terms.Let the sequence be $a_1, a_2, a_3, \dots$ where $a_1 = \frac{

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$A.P.$

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(C) To determine the type of sequence,we check the difference between consecutive terms.Let the sequence be $a_1, a_2, a_3, \dots$ where $a_1 = \frac{5}{\sqrt{7}}$,$a_2 = \frac{6}{\sqrt{7}}$,and $a_3 = \sqrt{7}$.The difference between the second and first term is $d_1 = a_2 - a_1 = \frac{6}{\sqrt{7}} - \frac{5}{\sqrt{7}} = \frac{1}{\sqrt{7}}$.The difference between the third and second term is $d_2 = a_3 - a_2 = \sqrt{7} - \frac{6}{\sqrt{7}}$.Since $\sqrt{7} = \frac{\sqrt{7} 	imes \sqrt{7}}{\sqrt{7}} = \frac{7}{\sqrt{7}}$,we have $d_2 = \frac{7}{\sqrt{7}} - \frac{6}{\sqrt{7}} = \frac{1}{\sqrt{7}}$.Since $d_1 = d_2 = \frac{1}{\sqrt{7}}$,the common difference is constant.Therefore,the sequence is an $A.P.$ (Arithmetic Progression).

The sequence $\frac{5}{\sqrt{7}}, \frac{6}{\sqrt{7}}, \sqrt{7}, \dots$ is

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