The set of values of x for which the expressi | vedclass

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(A) The given expression is $\frac{	an 3x - 	an 2x}{1 + 	an 3x 	an 2x} = 1$.Using the identity $	an(A - B) = \frac{	an A - 	an B}{1 + 	an A

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$\phi$

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(A) The given expression is $\frac{	an 3x - 	an 2x}{1 + 	an 3x 	an 2x} = 1$.Using the identity $	an(A - B) = \frac{	an A - 	an B}{1 + 	an A 	an B}$,we get $	an(3x - 2x) = 1$,which simplifies to $	an x = 1$.The general solution for $	an x = 1$ is $x = n\pi + \frac{\pi}{4}$ for $n \in \mathbb{Z}$.However,we must check the domain of the original expression. The expression is undefined if $	an 3x$ or $	an 2x$ is undefined,or if $1 + 	an 3x 	an 2x = 0$.If $x = n\pi + \frac{\pi}{4}$,then $3x = 3n\pi + \frac{3\pi}{4}$ and $2x = 2n\pi + \frac{\pi}{2}$.Since $	an 2x = 	an(2n\pi + \frac{\pi}{2})$ is undefined,the expression is undefined for all $x = n\pi + \frac{\pi}{4}$.Therefore,there are no values of $x$ that satisfy the equation.The correct set is $\phi$.

The set of values of $x$ for which the expression $\frac{\tan 3x - \tan 2x}{1 + \tan 3x \tan 2x} = 1$ is

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