The shaded region in the figure is the soluti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Identify the equations of the lines from their intercepts:- Line passing through $(0, 4)$ and $(5, 0)$: $\frac{x}{5} + \frac{y}{4} = 1 \Right

Vedclass · Accepted Answer

$4x + 5y \geq 20, 3x + 10y \leq 30, x \leq 6, x, y \geq 0$

Vedclass · Answer

(C) $1$. Identify the equations of the lines from their intercepts:- Line passing through $(0, 4)$ and $(5, 0)$: $\frac{x}{5} + \frac{y}{4} = 1 \Rightarrow 4x + 5y = 20$.- Line passing through $(0, 3)$ and $(10, 0)$: $\frac{x}{10} + \frac{y}{3} = 1 \Rightarrow 3x + 10y = 30$.- Vertical line passing through $(6, 0)$: $x = 6$.$2$. Determine the inequalities based on the shaded region:- The shaded region is above the line $4x + 5y = 20$,so the inequality is $4x + 5y \geq 20$.- The shaded region is below the line $3x + 10y = 30$,so the inequality is $3x + 10y \leq 30$.- The shaded region is to the left of the line $x = 6$,so the inequality is $x \leq 6$.- Since the region is in the first quadrant,$x, y \geq 0$.Thus,the correct set of inequations is $4x + 5y \geq 20, 3x + 10y \leq 30, x \leq 6, x, y \geq 0$.

The shaded region in the figure is the solution set of the inequations:

Similar Questions

Solve the following system of linear inequalities graphically:
$x+y \geq 5$ ..... $(1)$
$x-y \leq 3$ ..... $(2)$

Solve the following system of inequalities graphically: $x+y \leq 6, x+y \geq 4$

Solve the following system of inequalities graphically: $x - y + 2 \geq 0$ and $2x + y - 5 \leq 0$.

Solve the following system of inequalities graphically: $2x + y \leq 12, x + 2y \leq 7, x \geq 0, y \geq 0$.

The region represented by the inequalities $x \geq 6, y \geq 3, 2x + y \geq 10, x \geq 0, y \geq 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module