Solve the following system of inequalities gr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Consider the boundary lines $x - y + 2 = 0$ and $2x + y - 5 = 0$. Step $2$: For $x - y + 2 = 0$,if $x = 0$,$y = 2$; if $y = 0$,$x = -2$.

Vedclass · Accepted Answer

The solution is the intersection of the half-planes defined by $x - y \geq -2$ and $2x + y \leq 5$.

Vedclass · Answer

(B) Step $1$: Consider the boundary lines $x - y + 2 = 0$ and $2x + y - 5 = 0$. Step $2$: For $x - y + 2 = 0$,if $x = 0$,$y = 2$; if $y = 0$,$x = -2$. The line passes through $(0, 2)$ and $(-2, 0)$. Testing $(0, 0)$,$0 - 0 + 2 \geq 0$ is true,so the region includes the origin. Step $3$: For $2x + y - 5 = 0$,if $x = 0$,$y = 5$; if $y = 0$,$x = 2.5$. The line passes through $(0, 5)$ and $(2.5, 0)$. Testing $(0, 0)$,$2(0) + 0 - 5 \leq 0$ is true,so the region includes the origin. Step $4$: The solution is the common shaded region satisfying both inequalities simultaneously.

Solve the following system of inequalities graphically: $x - y + 2 \geq 0$ and $2x + y - 5 \leq 0$.

Similar Questions

Solve the following system of inequalities graphically: $x+y \leq 9, y>x, x \geq 0$.

The shaded region given in the figure represents the $\ldots \ldots \ldots$ inequality.

The shaded region in the provided graph represents the solution set for which of the following systems of linear inequalities?

The set $\{x \in R: \frac{14x}{x+1} - \frac{9x-30}{x-4} < 0\}$ is equal to

Find the linear inequalities for which the shaded region in the given figure is the solution set.

Vedclass Test Series

Exam Paper Generator

Online Exam Module