The shortest distance between the lines $\frac{x-1}{0}=\frac{y+1}{-1}=\frac{z}{1}$ and $x+y+z+1=0, 2x-y+z+3=0$ is

  • A
    $\frac{1}{2}$
  • B
    $1$
  • C
    $\frac{1}{\sqrt{2}}$
  • D
    $\frac{1}{\sqrt{3}}$

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